$_ = 'somestring';
`$_`; // backticks are shell or exec(), $_ is the previous string.
type echo "'^#(/||/@!@[{@:^[-['^";@@@\\>])@."."{)/];)^{";$,+=(++$,);$_.=">&$," to see what it does;$,+=(++$,); looks like a for loop
looks like php to me - backticks work in perl, bash and php
The $ vars lead me to either Shell, Perl or PHP.
$_ is a special var in Bash and Perl.
The '.' char is for string concat in Perl and PHP
So, I think this is perl.
The first statement evaluates to: "echo Brian Rogers >&2" The second statement `$_` runs that command.
The end result is that this line of code prints:
Brian Rogers
It's Perl. The last `$_`; evals what's in $_, so change it to just print the variable:
$_='^#(/||/@!@[{@:^[-['^";@@@\\>])@.".
"{)/];)^{";$,+=(++$,);$_.=">&$,";
print "$_";
The output is: echo Brian Rogers >&2Look like a regular expression.
Original Code
$ man perlop= Assignment Operator.
. Concatenation Operator.
.= Concatenate and Assign.
^ Binary XOR. The binary "^" and "|" operators have lower precedence than relational operators like concatenate.
' Text between single quotes is an uninterpreted string.
" Text between double quotes is an interpreted string.
; Statement terminator, just like C, java, javascript, ...
$ man perlvar
$_ The default input and pattern-searching space. A lot of perl code operates on this variable by default.
$, The output field separator for the print operator. If defined, this value is printed between each of print's arguments. The default is "undef".
The first statement is:
$_='^#(/||/@!@[{@:^[-['^";@@@\\>])@."."{)/];)^{";
String1: '^#(/||/@!@[{@:^[-['
String2: ";@@@\\>])@."
String3: "{)/];)^{"
So we get:
Result = String1 XOR String2 CONCAT String3
Since XOR has a lower precedence than Concatenate, we Concatenate first and then do the XOR.
Note: You should ask your friend Brian Rodgers if he always writes his name to Standard ERROR! ;)